What are the solutions to the equation 5x^2+2x=10 ?

The solutions to the equation 5x^2+2x=10 are x=(-1+sqrt(51))/5 ,x=-(1+sqrt(51))/5

Find the zeros of 5x^2+2x=10

The zeros of 5x^2+2x=10 are x=(-1+sqrt(51))/5 ,x=-(1+sqrt(51))/5

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5 x^{2} + 2 x = 10

x = \frac{- 1 + 51}{5}, x = - \frac{1 + 51}{5}

Decimal Notation

x = 1.22828 \dots, x = - 1.62828 \dots

Solution steps

5 x^{2} + 2 x = 10

Move

10

to the left side

5 x^{2} + 2 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 ( - 10 )}{2 \cdot 5}

2^{2} - 4 \cdot 5 (- 10) = 251

x_{1, 2} = \frac{- 2 \pm 2 51}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 2 + 2 51}{2 \cdot 5}, x_{2} = \frac{- 2 - 2 51}{2 \cdot 5}

x = \frac{- 2 + 2 51}{2 \cdot 5} : \frac{- 1 + 51}{5}

x = \frac{- 2 - 2 51}{2 \cdot 5} : - \frac{1 + 51}{5}

The solutions to the quadratic equation are:

x = \frac{- 1 + 51}{5}, x = - \frac{1 + 51}{5}

2 x^{2} - x - 1 = 0

(x + 1) (2 x - 1) + \frac{x}{2} = 4 x^{2} - 3

3 x^{2} = 432

x (x + 4) = 4

x^{2} + 25 x + 100 = 0

What are the solutions to the equation 5x^2+2x=10 ?
The solutions to the equation 5x^2+2x=10 are x=(-1+sqrt(51))/5 ,x=-(1+sqrt(51))/5
Find the zeros of 5x^2+2x=10
The zeros of 5x^2+2x=10 are x=(-1+sqrt(51))/5 ,x=-(1+sqrt(51))/5