What are the solutions to the equation x(x+4)=4 ?

The solutions to the equation x(x+4)=4 are x=2(sqrt(2)-1),x=-2(1+sqrt(2))

Find the zeros of x(x+4)=4

The zeros of x(x+4)=4 are x=2(sqrt(2)-1),x=-2(1+sqrt(2))

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x (x + 4) = 4

x = 2 (2 - 1), x = - 2 (1 + 2)

Decimal Notation

x = 0.82842 \dots, x = - 4.82842 \dots

Solution steps

x (x + 4) = 4

Expand

x (x + 4) : x^{2} + 4 x

x^{2} + 4 x = 4

Move

4

to the left side

x^{2} + 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 4) = 42

x_{1, 2} = \frac{- 4 \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 2}{2 \cdot 1}

x = \frac{- 4 + 4 2}{2 \cdot 1} : 2 (2 - 1)

x = \frac{- 4 - 4 2}{2 \cdot 1} : - 2 (1 + 2)

The solutions to the quadratic equation are:

x = 2 (2 - 1), x = - 2 (1 + 2)

x^{2} + 25 x + 100 = 0

3 x^{2} - 20 x + 17 = 0

3 x^{2} - 3 x + 6 = 0

12 x^{2} - 12 x + 2 = 0

x^{2} = 4 \cdot 9

What are the solutions to the equation x(x+4)=4 ?
The solutions to the equation x(x+4)=4 are x=2(sqrt(2)-1),x=-2(1+sqrt(2))
Find the zeros of x(x+4)=4
The zeros of x(x+4)=4 are x=2(sqrt(2)-1),x=-2(1+sqrt(2))