What are the solutions to the equation (x-1/3)^2= 4/9 ?

The solutions to the equation (x-1/3)^2= 4/9 are x=1,x=-1/3

Find the zeros of (x-1/3)^2= 4/9

The zeros of (x-1/3)^2= 4/9 are x=1,x=-1/3

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(x - \frac{1}{3})^{2} = \frac{4}{9}

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

(x - \frac{1}{3})^{2} = \frac{4}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - \frac{1}{3} = \frac{4}{9} : x = 1

Solve

x - \frac{1}{3} = - \frac{4}{9} : x = - \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{3}

8^{2} + 1 1^{2} = c^{2}

(x + 8) (x + 11) = 0

2 x^{2} + 6 x + 11 = 2 x

15 x^{2} + 1 = 0

3 r^{2} - 16 r - 12 = 0

What are the solutions to the equation (x-1/3)^2= 4/9 ?
The solutions to the equation (x-1/3)^2= 4/9 are x=1,x=-1/3
Find the zeros of (x-1/3)^2= 4/9
The zeros of (x-1/3)^2= 4/9 are x=1,x=-1/3