What are the solutions to the equation 192=(2x+12)(2x+8) ?

The solutions to the equation 192=(2x+12)(2x+8) are x=2,x=-12

Find the zeros of 192=(2x+12)(2x+8)

The zeros of 192=(2x+12)(2x+8) are x=2,x=-12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

192 = (2 x + 12) (2 x + 8)

x = 2, x = - 12

Solution steps

192 = (2 x + 12) (2 x + 8)

Expand

(2 x + 12) (2 x + 8) : 4 x^{2} + 40 x + 96

192 = 4 x^{2} + 40 x + 96

Switch sides

4 x^{2} + 40 x + 96 = 192

Move

192

to the left side

4 x^{2} + 40 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 4 ( - 96 )}{2 \cdot 4}

4 0^{2} - 4 \cdot 4 (- 96) = 56

x_{1, 2} = \frac{- 40 \pm 56}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 40 + 56}{2 \cdot 4}, x_{2} = \frac{- 40 - 56}{2 \cdot 4}

x = \frac{- 40 + 56}{2 \cdot 4} : 2

x = \frac{- 40 - 56}{2 \cdot 4} : - 12

The solutions to the quadratic equation are:

x = 2, x = - 12

- 2 x^{2} + 11 x - 14 = 0

(2 x + 3) (x - 2) = 5 (x - 2)

9 x^{2} - 12 x + 1 = 0

p^{2} - 5 p - 6 = 0

7 x^{2} - 4 x - 8 = 0

What are the solutions to the equation 192=(2x+12)(2x+8) ?
The solutions to the equation 192=(2x+12)(2x+8) are x=2,x=-12
Find the zeros of 192=(2x+12)(2x+8)
The zeros of 192=(2x+12)(2x+8) are x=2,x=-12