What are the solutions to the equation 9x^2-12x+1=0 ?

The solutions to the equation 9x^2-12x+1=0 are x=(2+sqrt(3))/3 ,x=(2-sqrt(3))/3

Find the zeros of 9x^2-12x+1=0

The zeros of 9x^2-12x+1=0 are x=(2+sqrt(3))/3 ,x=(2-sqrt(3))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} - 12 x + 1 = 0

x = \frac{2 + 3}{3}, x = \frac{2 - 3}{3}

Decimal Notation

x = 1.24401 \dots, x = 0.08931 \dots

Solution steps

9 x^{2} - 12 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 1 = 63

x_{1, 2} = \frac{- ( - 12 ) \pm 6 3}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 3}{2 \cdot 9}, x_{2} = \frac{- ( - 12 ) - 6 3}{2 \cdot 9}

x = \frac{- ( - 12 ) + 6 3}{2 \cdot 9} : \frac{2 + 3}{3}

x = \frac{- ( - 12 ) - 6 3}{2 \cdot 9} : \frac{2 - 3}{3}

The solutions to the quadratic equation are:

x = \frac{2 + 3}{3}, x = \frac{2 - 3}{3}

p^{2} - 5 p - 6 = 0

7 x^{2} - 4 x - 8 = 0

x^{2} + 8.5 x + 18 = 0

(2 x - 3)^{2} - 1 = 0

x^{2} - 16 x + 145 = 0

What are the solutions to the equation 9x^2-12x+1=0 ?
The solutions to the equation 9x^2-12x+1=0 are x=(2+sqrt(3))/3 ,x=(2-sqrt(3))/3
Find the zeros of 9x^2-12x+1=0
The zeros of 9x^2-12x+1=0 are x=(2+sqrt(3))/3 ,x=(2-sqrt(3))/3