What are the solutions to the equation x^2-3x+9/4 =6 ?

The solutions to the equation x^2-3x+9/4 =6 are x=(3+2sqrt(6))/2 ,x=(3-2sqrt(6))/2

Find the zeros of x^2-3x+9/4 =6

The zeros of x^2-3x+9/4 =6 are x=(3+2sqrt(6))/2 ,x=(3-2sqrt(6))/2

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x^{2} - 3 x + \frac{9}{4} = 6

x = \frac{3 + 2 6}{2}, x = \frac{3 - 2 6}{2}

Decimal Notation

x = 3.94948 \dots, x = - 0.94948 \dots

Solution steps

x^{2} - 3 x + \frac{9}{4} = 6

Multiply both sides by

4

4 x^{2} - 12 x + 9 = 24

Move

24

to the left side

4 x^{2} - 12 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 15) = 86

x_{1, 2} = \frac{- ( - 12 ) \pm 8 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8 6}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 8 6}{2 \cdot 4}

x = \frac{- ( - 12 ) + 8 6}{2 \cdot 4} : \frac{3 + 2 6}{2}

x = \frac{- ( - 12 ) - 8 6}{2 \cdot 4} : \frac{3 - 2 6}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 2 6}{2}, x = \frac{3 - 2 6}{2}

1 2^{2} + 8^{2} = c^{2}

3 x^{2} - 12 x + 7

3 x^{2} - 12 x + 8

- 2 x^{2} + 5 x + 10 = 0

3 x^{2} - 1 = 14

What are the solutions to the equation x^2-3x+9/4 =6 ?
The solutions to the equation x^2-3x+9/4 =6 are x=(3+2sqrt(6))/2 ,x=(3-2sqrt(6))/2
Find the zeros of x^2-3x+9/4 =6
The zeros of x^2-3x+9/4 =6 are x=(3+2sqrt(6))/2 ,x=(3-2sqrt(6))/2