What are the solutions to the equation x^2+18x=-81 ?

The solutions to the equation x^2+18x=-81 are x=-9

Find the zeros of x^2+18x=-81

The zeros of x^2+18x=-81 are x=-9

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x^{2} + 18 x = - 81

x = - 9

Solution steps

x^{2} + 18 x = - 81

Move

81

to the left side

x^{2} + 18 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 81 = 0

x_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 1}

x = \frac{- 18}{2 \cdot 1}

\frac{- 18}{2 \cdot 1} = - 9

x = - 9

The solution to the quadratic equation is:

x = - 9

3 - (x - 2)^{2} = 7

0 = x^{2} - 5 x - 14

8 x^{2} + 6 x - 2 = 0

6 x^{2} = 3 x

5 x^{2} + 75 = 0

What are the solutions to the equation x^2+18x=-81 ?
The solutions to the equation x^2+18x=-81 are x=-9
Find the zeros of x^2+18x=-81
The zeros of x^2+18x=-81 are x=-9