What are the solutions to the equation 9y^2-12y+4=0 ?

The solutions to the equation 9y^2-12y+4=0 are y= 2/3

Find the zeros of 9y^2-12y+4=0

The zeros of 9y^2-12y+4=0 are y= 2/3

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9 y^{2} - 12 y + 4 = 0

y = \frac{2}{3}

Decimal Notation

y = 0.66666 \dots

Solution steps

9 y^{2} - 12 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

y_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

y = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

y = \frac{2}{3}

The solution to the quadratic equation is:

y = \frac{2}{3}

r^{2} - 5 r - 6 = 0

5 x^{2} + 170 = 60 x

x, x^{2} - x y + y^{2} = 6

x, x^{2} - x y + y^{2} = 2

10 0^{2} + x^{2} = 20 0^{2}

What are the solutions to the equation 9y^2-12y+4=0 ?
The solutions to the equation 9y^2-12y+4=0 are y= 2/3
Find the zeros of 9y^2-12y+4=0
The zeros of 9y^2-12y+4=0 are y= 2/3