What are the solutions to the equation 1/2 x^2+6x-5=0 ?

The solutions to the equation 1/2 x^2+6x-5=0 are x=-6+sqrt(46),x=-6-sqrt(46)

Find the zeros of 1/2 x^2+6x-5=0

The zeros of 1/2 x^2+6x-5=0 are x=-6+sqrt(46),x=-6-sqrt(46)

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\frac{1}{2} x^{2} + 6 x - 5 = 0

x = - 6 + 46, x = - 6 - 46

Decimal Notation

x = 0.78232 \dots, x = - 12.78232 \dots

Solution steps

\frac{1}{2} x^{2} + 6 x - 5 = 0

Multiply both sides by

2

x^{2} + 12 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 10) = 246

x_{1, 2} = \frac{- 12 \pm 2 46}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 46}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 46}{2 \cdot 1}

x = \frac{- 12 + 2 46}{2 \cdot 1} : - 6 + 46

x = \frac{- 12 - 2 46}{2 \cdot 1} : - 6 - 46

The solutions to the quadratic equation are:

x = - 6 + 46, x = - 6 - 46

2 (x + 3)^{2} - 120 = 0

3 - 2 x^{2} = 0

14 x^{2} + 35 x = 0

x^{2} + 8 x + 10

x^{2} + 8 x + 14

What are the solutions to the equation 1/2 x^2+6x-5=0 ?
The solutions to the equation 1/2 x^2+6x-5=0 are x=-6+sqrt(46),x=-6-sqrt(46)
Find the zeros of 1/2 x^2+6x-5=0
The zeros of 1/2 x^2+6x-5=0 are x=-6+sqrt(46),x=-6-sqrt(46)