What are the solutions to the equation -4x^2+3x+1=0 ?

The solutions to the equation -4x^2+3x+1=0 are x=-1/4 ,x=1

Find the zeros of -4x^2+3x+1=0

The zeros of -4x^2+3x+1=0 are x=-1/4 ,x=1

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- 4 x^{2} + 3 x + 1 = 0

x = - \frac{1}{4}, x = 1

Decimal Notation

x = - 0.25, x = 1

Solution steps

- 4 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) \cdot 1}{2 ( - 4 )}

3^{2} - 4 (- 4) \cdot 1 = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 ( - 4 )}, x_{2} = \frac{- 3 - 5}{2 ( - 4 )}

x = \frac{- 3 + 5}{2 ( - 4 )} : - \frac{1}{4}

x = \frac{- 3 - 5}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = 1

x^{2} + 2 x + 5 = 0

- 4 x^{2} = 3 x - 1

2 0^{2} + x^{2} = 2 9^{2}

x^{2} + (x + 10)^{2} = 5 0^{2}

5 x^{2} + x + 7 = - 2 x^{2} + 8 x - 1

What are the solutions to the equation -4x^2+3x+1=0 ?
The solutions to the equation -4x^2+3x+1=0 are x=-1/4 ,x=1
Find the zeros of -4x^2+3x+1=0
The zeros of -4x^2+3x+1=0 are x=-1/4 ,x=1