What are the solutions to the equation 3x^2-4x-1=2x^2-5 ?

The solutions to the equation 3x^2-4x-1=2x^2-5 are x=2

Find the zeros of 3x^2-4x-1=2x^2-5

The zeros of 3x^2-4x-1=2x^2-5 are x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 4 x - 1 = 2 x^{2} - 5

x = 2

Solution steps

3 x^{2} - 4 x - 1 = 2 x^{2} - 5

Move

5

to the left side

3 x^{2} - 4 x + 4 = 2 x^{2}

Move

2 x^{2}

to the left side

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

4 x^{2} + x - 5 = - 6 x

4 x^{2} + 3 x = x (2 x - 2)

(x - 6) (2 x + 1) = 0

12 x = - 4 x^{2}

x^{2} - 2 a x + a^{2} + b^{2} = 0

What are the solutions to the equation 3x^2-4x-1=2x^2-5 ?
The solutions to the equation 3x^2-4x-1=2x^2-5 are x=2
Find the zeros of 3x^2-4x-1=2x^2-5
The zeros of 3x^2-4x-1=2x^2-5 are x=2