What are the solutions to the equation completesquare 4x^2+3x=x(2x-2) ?

The solutions to the equation completesquare 4x^2+3x=x(2x-2) are x=0,x=-5/2

Find the zeros of completesquare 4x^2+3x=x(2x-2)

The zeros of completesquare 4x^2+3x=x(2x-2) are x=0,x=-5/2

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4 x^{2} + 3 x = x (2 x - 2)

x = 0, x = - \frac{5}{2}

Decimal Notation

x = 0, x = - 2.5

Solution steps

4 x^{2} + 3 x = x (2 x - 2)

Expand

x (2 x - 2) : 2 x^{2} - 2 x

4 x^{2} + 3 x = 2 x^{2} - 2 x

Move

2 x

to the left side

4 x^{2} + 5 x = 2 x^{2}

Move

2 x^{2}

to the left side

2 x^{2} + 5 x = 0

Divide both sides by

2

\frac{2 x ^{2} + 5 x}{2} = \frac{0}{2}

x^{2} + \frac{5 x}{2} = 0

Rewrite in the form

(x + a)^{2} = b

(x + \frac{5}{4})^{2} = \frac{25}{16}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{5}{4} = \frac{25}{16} : x = 0

Solve

x + \frac{5}{4} = - \frac{25}{16} : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{5}{2}

(x - 6) (2 x + 1) = 0

12 x = - 4 x^{2}

x^{2} - 2 a x + a^{2} + b^{2} = 0

x^{2} + 15 x = - 57

5 y^{2} = - 25 y

What are the solutions to the equation completesquare 4x^2+3x=x(2x-2) ?
The solutions to the equation completesquare 4x^2+3x=x(2x-2) are x=0,x=-5/2
Find the zeros of completesquare 4x^2+3x=x(2x-2)
The zeros of completesquare 4x^2+3x=x(2x-2) are x=0,x=-5/2