What are the solutions to the equation -4x^2+6x+16=0 ?

The solutions to the equation -4x^2+6x+16=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4

Find the zeros of -4x^2+6x+16=0

The zeros of -4x^2+6x+16=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4

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- 4 x^{2} + 6 x + 16 = 0

x = - \frac{- 3 + 73}{4}, x = \frac{3 + 73}{4}

Decimal Notation

x = - 1.38600 \dots, x = 2.88600 \dots

Solution steps

- 4 x^{2} + 6 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 4 ) \cdot 16}{2 ( - 4 )}

6^{2} - 4 (- 4) \cdot 16 = 273

x_{1, 2} = \frac{- 6 \pm 2 73}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 73}{2 ( - 4 )}, x_{2} = \frac{- 6 - 2 73}{2 ( - 4 )}

x = \frac{- 6 + 2 73}{2 ( - 4 )} : - \frac{- 3 + 73}{4}

x = \frac{- 6 - 2 73}{2 ( - 4 )} : \frac{3 + 73}{4}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 73}{4}, x = \frac{3 + 73}{4}

x^{2} - 2 (x - 1) = 0

x^{2} + (x + 3)^{2} = 9

4 x^{2} - 4 x - 11 = 0

3 x^{2} - 8 x + 5 = 5 x^{2}

x^{2} + 3 - 4 = 0

What are the solutions to the equation -4x^2+6x+16=0 ?
The solutions to the equation -4x^2+6x+16=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4
Find the zeros of -4x^2+6x+16=0
The zeros of -4x^2+6x+16=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4