What are the solutions to the equation 3x^2-16x+1=-4 ?

The solutions to the equation 3x^2-16x+1=-4 are x=5,x= 1/3

Find the zeros of 3x^2-16x+1=-4

The zeros of 3x^2-16x+1=-4 are x=5,x= 1/3

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3 x^{2} - 16 x + 1 = - 4

x = 5, x = \frac{1}{3}

Decimal Notation

x = 5, x = 0.33333 \dots

Solution steps

3 x^{2} - 16 x + 1 = - 4

Move

4

to the left side

3 x^{2} - 16 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 \cdot 5 = 14

x_{1, 2} = \frac{- ( - 16 ) \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 14}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 14}{2 \cdot 3}

x = \frac{- ( - 16 ) + 14}{2 \cdot 3} : 5

x = \frac{- ( - 16 ) - 14}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 5, x = \frac{1}{3}

t^{2} + 7 t = 0

- x^{2} = 1

x^{2} - 6 x + 9 = 9

7 x^{2} - 18 x - 9 = 0

(x + 1)^{2} = 6

What are the solutions to the equation 3x^2-16x+1=-4 ?
The solutions to the equation 3x^2-16x+1=-4 are x=5,x= 1/3
Find the zeros of 3x^2-16x+1=-4
The zeros of 3x^2-16x+1=-4 are x=5,x= 1/3