What are the solutions to the equation (x+1)^2=6 ?

The solutions to the equation (x+1)^2=6 are x=sqrt(6)-1,x=-sqrt(6)-1

Find the zeros of (x+1)^2=6

The zeros of (x+1)^2=6 are x=sqrt(6)-1,x=-sqrt(6)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 1)^{2} = 6

x = 6 - 1, x = - 6 - 1

Decimal Notation

x = 1.44948 \dots, x = - 3.44948 \dots

Solution steps

(x + 1)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 6 : x = 6 - 1

Solve

x + 1 = - 6 : x = - 6 - 1

The solutions to the quadratic equation are:

x = 6 - 1, x = - 6 - 1

2 x^{2} - 16 x + 5 = 0

7 x^{2} + 4 = - 24

x^{2} = 2 - 2 x

- x^{2} + 8 x - 7

x, x^{2} + x y + y^{2} - 7 = 0

What are the solutions to the equation (x+1)^2=6 ?
The solutions to the equation (x+1)^2=6 are x=sqrt(6)-1,x=-sqrt(6)-1
Find the zeros of (x+1)^2=6
The zeros of (x+1)^2=6 are x=sqrt(6)-1,x=-sqrt(6)-1