What are the solutions to the equation x^2=2-2x ?

The solutions to the equation x^2=2-2x are x=-1+sqrt(3),x=-1-sqrt(3)

Find the zeros of x^2=2-2x

The zeros of x^2=2-2x are x=-1+sqrt(3),x=-1-sqrt(3)

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x^{2} = 2 - 2 x

x = - 1 + 3, x = - 1 - 3

Decimal Notation

x = 0.73205 \dots, x = - 2.73205 \dots

Solution steps

x^{2} = 2 - 2 x

Move

2 x

to the left side

x^{2} + 2 x = 2

Move

2

to the left side

x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

x = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

x = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

x = - 1 + 3, x = - 1 - 3

- x^{2} + 8 x - 7

x, x^{2} + x y + y^{2} - 7 = 0

x^{2} - 4 = 8 - 2 x^{2}

- 8 x^{2} + \frac{8 10}{5} x

x, x^{2} + 4 y^{2} + 9 z^{2} = 1

What are the solutions to the equation x^2=2-2x ?
The solutions to the equation x^2=2-2x are x=-1+sqrt(3),x=-1-sqrt(3)
Find the zeros of x^2=2-2x
The zeros of x^2=2-2x are x=-1+sqrt(3),x=-1-sqrt(3)