What are the solutions to the equation x^2-4=8-2x^2 ?

The solutions to the equation x^2-4=8-2x^2 are x=2,x=-2

Find the zeros of x^2-4=8-2x^2

The zeros of x^2-4=8-2x^2 are x=2,x=-2

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x^{2} - 4 = 8 - 2 x^{2}

x = 2, x = - 2

Solution steps

x^{2} - 4 = 8 - 2 x^{2}

Move

4

to the right side

x^{2} = - 2 x^{2} + 12

Move

2 x^{2}

to the left side

3 x^{2} = 12

Divide both sides by

3

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

- 8 x^{2} + \frac{8 10}{5} x

x, x^{2} + 4 y^{2} + 9 z^{2} = 1

x^{2} + 17 x

- 3 x^{2} - 18 x = 0

1 - 2 x - x^{2} = 0

What are the solutions to the equation x^2-4=8-2x^2 ?
The solutions to the equation x^2-4=8-2x^2 are x=2,x=-2
Find the zeros of x^2-4=8-2x^2
The zeros of x^2-4=8-2x^2 are x=2,x=-2