What are the solutions to the equation 0=2x^2-4x-1 ?

The solutions to the equation 0=2x^2-4x-1 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2

Find the zeros of 0=2x^2-4x-1

The zeros of 0=2x^2-4x-1 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 2 x^{2} - 4 x - 1

x = \frac{2 + 6}{2}, x = \frac{2 - 6}{2}

Decimal Notation

x = 2.22474 \dots, x = - 0.22474 \dots

Solution steps

0 = 2 x^{2} - 4 x - 1

Switch sides

2 x^{2} - 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 1) = 26

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 2 6}{2 \cdot 2}

x = \frac{- ( - 4 ) + 2 6}{2 \cdot 2} : \frac{2 + 6}{2}

x = \frac{- ( - 4 ) - 2 6}{2 \cdot 2} : \frac{2 - 6}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 6}{2}, x = \frac{2 - 6}{2}

9 x^{2} + 36 x + 72 = 0

x, y^{2} + x^{2} = 0

8 x^{2} + 10 x = - 3

3 x^{2} - 6 x = 2

x^{2} + 2 + 1 = 0

What are the solutions to the equation 0=2x^2-4x-1 ?
The solutions to the equation 0=2x^2-4x-1 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2
Find the zeros of 0=2x^2-4x-1
The zeros of 0=2x^2-4x-1 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2