What are the solutions to the equation p^2-8p+21=6 ?

The solutions to the equation p^2-8p+21=6 are p=5,p=3

Find the zeros of p^2-8p+21=6

The zeros of p^2-8p+21=6 are p=5,p=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p^{2} - 8 p + 21 = 6

p = 5, p = 3

Solution steps

p^{2} - 8 p + 21 = 6

Move

6

to the left side

p^{2} - 8 p + 15 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

p_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, p_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

p = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

p = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

p = 5, p = 3

6 x^{2} + 48 = 0

x^{2} - 2 x^{2} = 0

9 x^{2} + 12 x = - 4

2 x^{2} + 4 x + 0 = 0

0 = 12 x^{2}

What are the solutions to the equation p^2-8p+21=6 ?
The solutions to the equation p^2-8p+21=6 are p=5,p=3
Find the zeros of p^2-8p+21=6
The zeros of p^2-8p+21=6 are p=5,p=3