What are the solutions to the equation 12^2+15^2=c^2 ?

The solutions to the equation 12^2+15^2=c^2 are c=3sqrt(41),c=-3sqrt(41)

Find the zeros of 12^2+15^2=c^2

The zeros of 12^2+15^2=c^2 are c=3sqrt(41),c=-3sqrt(41)

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1 2^{2} + 1 5^{2} = c^{2}

c = 341, c = - 341

Decimal Notation

c = 19.20937 \dots, c = - 19.20937 \dots

Solution steps

1 2^{2} + 1 5^{2} = c^{2}

Switch sides

c^{2} = 1 2^{2} + 1 5^{2}

Simplify

1 2^{2} + 1 5^{2} : 369

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 369, c = - 369

369 = 341

- 369 = - 341

c = 341, c = - 341

y^{2} - 3 y + 3 = 0

5 x^{2} - 6 x - 7 = 0

I, P = I^{2} R

2 x^{2} - 6 x = 0

m^{2} + 7 m + 12 = 0

What are the solutions to the equation 12^2+15^2=c^2 ?
The solutions to the equation 12^2+15^2=c^2 are c=3sqrt(41),c=-3sqrt(41)
Find the zeros of 12^2+15^2=c^2
The zeros of 12^2+15^2=c^2 are c=3sqrt(41),c=-3sqrt(41)