What are the solutions to the equation m^2+7m+12=0 ?

The solutions to the equation m^2+7m+12=0 are m=-3,m=-4

Find the zeros of m^2+7m+12=0

The zeros of m^2+7m+12=0 are m=-3,m=-4

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m^{2} + 7 m + 12 = 0

m = - 3, m = - 4

Solution steps

m^{2} + 7 m + 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

m_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 7 + 1}{2 \cdot 1}, m_{2} = \frac{- 7 - 1}{2 \cdot 1}

m = \frac{- 7 + 1}{2 \cdot 1} : - 3

m = \frac{- 7 - 1}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

m = - 3, m = - 4

x^{2} - 4 x = 14 - 9 x

- x^{2} - 20 x - 67 = - 3

2 x^{2} - 3 x - 5

2 x^{2} - 3 x - 1

\frac{1}{3} x^{2} + 10 = 7

What are the solutions to the equation m^2+7m+12=0 ?
The solutions to the equation m^2+7m+12=0 are m=-3,m=-4
Find the zeros of m^2+7m+12=0
The zeros of m^2+7m+12=0 are m=-3,m=-4