What are the solutions to the equation x^2-4x=14-9x ?

The solutions to the equation x^2-4x=14-9x are x=2,x=-7

Find the zeros of x^2-4x=14-9x

The zeros of x^2-4x=14-9x are x=2,x=-7

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x^{2} - 4 x = 14 - 9 x

x = 2, x = - 7

Solution steps

x^{2} - 4 x = 14 - 9 x

Move

9 x

to the left side

x^{2} + 5 x = 14

Move

14

to the left side

x^{2} + 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 9}{2 \cdot 1}, x_{2} = \frac{- 5 - 9}{2 \cdot 1}

x = \frac{- 5 + 9}{2 \cdot 1} : 2

x = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 2, x = - 7

- x^{2} - 20 x - 67 = - 3

2 x^{2} - 3 x - 5

2 x^{2} - 3 x - 1

\frac{1}{3} x^{2} + 10 = 7

v^{2} - 4 v

What are the solutions to the equation x^2-4x=14-9x ?
The solutions to the equation x^2-4x=14-9x are x=2,x=-7
Find the zeros of x^2-4x=14-9x
The zeros of x^2-4x=14-9x are x=2,x=-7