What are the solutions to the equation -x^2-20x-67=-3 ?

The solutions to the equation -x^2-20x-67=-3 are x=-16,x=-4

Find the zeros of -x^2-20x-67=-3

The zeros of -x^2-20x-67=-3 are x=-16,x=-4

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- x^{2} - 20 x - 67 = - 3

x = - 16, x = - 4

Solution steps

- x^{2} - 20 x - 67 = - 3

Move

3

to the left side

- x^{2} - 20 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 1 ) ( - 64 )}{2 ( - 1 )}

(- 20)^{2} - 4 (- 1) (- 64) = 12

x_{1, 2} = \frac{- ( - 20 ) \pm 12}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 12}{2 ( - 1 )}, x_{2} = \frac{- ( - 20 ) - 12}{2 ( - 1 )}

x = \frac{- ( - 20 ) + 12}{2 ( - 1 )} : - 16

x = \frac{- ( - 20 ) - 12}{2 ( - 1 )} : - 4

The solutions to the quadratic equation are:

x = - 16, x = - 4

2 x^{2} - 3 x - 5

2 x^{2} - 3 x - 1

\frac{1}{3} x^{2} + 10 = 7

v^{2} - 4 v

p^{2} - 2 p - 14 = - 6

What are the solutions to the equation -x^2-20x-67=-3 ?
The solutions to the equation -x^2-20x-67=-3 are x=-16,x=-4
Find the zeros of -x^2-20x-67=-3
The zeros of -x^2-20x-67=-3 are x=-16,x=-4