What are the solutions to the equation 3x^2=7+5x ?

The solutions to the equation 3x^2=7+5x are x=(5+sqrt(109))/6 ,x=(5-sqrt(109))/6

Find the zeros of 3x^2=7+5x

The zeros of 3x^2=7+5x are x=(5+sqrt(109))/6 ,x=(5-sqrt(109))/6

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3 x^{2} = 7 + 5 x

x = \frac{5 + 109}{6}, x = \frac{5 - 109}{6}

Decimal

x = 2.57338 \dots, x = - 0.90671 \dots

Solution steps

3 x^{2} = 7 + 5 x

Move

5 x

to the left side

3 x^{2} - 5 x = 7

Move

7

to the left side

3 x^{2} - 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 7) = 109

x_{1, 2} = \frac{- ( - 5 ) \pm 109}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 109}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 109}{2 \cdot 3}

x = \frac{- ( - 5 ) + 109}{2 \cdot 3} : \frac{5 + 109}{6}

x = \frac{- ( - 5 ) - 109}{2 \cdot 3} : \frac{5 - 109}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 109}{6}, x = \frac{5 - 109}{6}

x^{2} - x - 17 = 3

x, z = 3 x^{2} + x y - 2 y^{2}

x, x^{2} + y^{2} + 2 x - 3 y + 6 = 0

(x + 5) (x + 2) + 2 = 0

x^{2} + 6 x + 8 = 0

What are the solutions to the equation 3x^2=7+5x ?
The solutions to the equation 3x^2=7+5x are x=(5+sqrt(109))/6 ,x=(5-sqrt(109))/6
Find the zeros of 3x^2=7+5x
The zeros of 3x^2=7+5x are x=(5+sqrt(109))/6 ,x=(5-sqrt(109))/6