What are the solutions to the equation 2x^2=-7x ?

The solutions to the equation 2x^2=-7x are x=0,x=-7/2

Find the zeros of 2x^2=-7x

The zeros of 2x^2=-7x are x=0,x=-7/2

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2 x^{2} = - 7 x

x = 0, x = - \frac{7}{2}

Decimal Notation

x = 0, x = - 3.5

Solution steps

2 x^{2} = - 7 x

Move

7 x

to the left side

2 x^{2} + 7 x = 0

Factor

2 x^{2} + 7 x : x (2 x + 7)

x (2 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 7 = 0

Solve

2 x + 7 = 0 : x = - \frac{7}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{7}{2}

t^{2} - 9 t - 10 = 0

2 x^{2} = - 50

- 31 x + 56 = - x^{2}

12 x^{2} - 36 x + 20 = 0

- 24 x^{2} + 6 = 0

What are the solutions to the equation 2x^2=-7x ?
The solutions to the equation 2x^2=-7x are x=0,x=-7/2
Find the zeros of 2x^2=-7x
The zeros of 2x^2=-7x are x=0,x=-7/2