What are the solutions to the equation d^2-2d=0 ?

The solutions to the equation d^2-2d=0 are d=2,d=0

Find the zeros of d^2-2d=0

The zeros of d^2-2d=0 are d=2,d=0

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d^{2} - 2 d = 0

d = 2, d = 0

Solution steps

d^{2} - 2 d = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

d_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, d_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

d = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

d = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

d = 2, d = 0

5 n^{2} + 19 n - 68 = - 2

3 x^{2} + 6 x + 78 = 0

0 = - 2 x^{2} + 8 x

p, p^{2} + 2 pq + q^{2} = 1

10 x^{2} - 6 x - 7 = 4 x^{2} + 7 x - 2

What are the solutions to the equation d^2-2d=0 ?
The solutions to the equation d^2-2d=0 are d=2,d=0
Find the zeros of d^2-2d=0
The zeros of d^2-2d=0 are d=2,d=0