What are the solutions to the equation r^2-10r=-17 ?

The solutions to the equation r^2-10r=-17 are r=5+2sqrt(2),r=5-2sqrt(2)

Find the zeros of r^2-10r=-17

The zeros of r^2-10r=-17 are r=5+2sqrt(2),r=5-2sqrt(2)

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r^{2} - 10 r = - 17

r = 5 + 22, r = 5 - 22

Decimal Notation

r = 7.82842 \dots, r = 2.17157 \dots

Solution steps

r^{2} - 10 r = - 17

Move

17

to the left side

r^{2} - 10 r + 17 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 17 = 42

r_{1, 2} = \frac{- ( - 10 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 10 ) + 4 2}{2 \cdot 1}, r_{2} = \frac{- ( - 10 ) - 4 2}{2 \cdot 1}

r = \frac{- ( - 10 ) + 4 2}{2 \cdot 1} : 5 + 22

r = \frac{- ( - 10 ) - 4 2}{2 \cdot 1} : 5 - 22

The solutions to the quadratic equation are:

r = 5 + 22, r = 5 - 22

x (x - 4) = 32

x (x - 4) = 12

x (10 x - 1) = 2

x^{2} - 12 x = - 24

x^{2} - 12 x = - 10

What are the solutions to the equation r^2-10r=-17 ?
The solutions to the equation r^2-10r=-17 are r=5+2sqrt(2),r=5-2sqrt(2)
Find the zeros of r^2-10r=-17
The zeros of r^2-10r=-17 are r=5+2sqrt(2),r=5-2sqrt(2)