What are the solutions to the equation x^2-12x=-10 ?

The solutions to the equation x^2-12x=-10 are x=6+sqrt(26),x=6-sqrt(26)

Find the zeros of x^2-12x=-10

The zeros of x^2-12x=-10 are x=6+sqrt(26),x=6-sqrt(26)

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x^{2} - 12 x = - 10

x = 6 + 26, x = 6 - 26

Decimal Notation

x = 11.09901 \dots, x = 0.90098 \dots

Solution steps

x^{2} - 12 x = - 10

Move

10

to the left side

x^{2} - 12 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 10 = 226

x_{1, 2} = \frac{- ( - 12 ) \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 26}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 26}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 26}{2 \cdot 1} : 6 + 26

x = \frac{- ( - 12 ) - 2 26}{2 \cdot 1} : 6 - 26

The solutions to the quadratic equation are:

x = 6 + 26, x = 6 - 26

4 x^{2} - 7 x - 1 = 0

2 x^{2} - 27 x + 12 = - 10 x - 19

x, x^{2} + y^{2} + 8 x - 6 y + 30 = 0

(2 x + 4) (2 x - 4) = (x - 8) (x + 3) + 6

3 x^{2} - 1 x - 4 = 0

What are the solutions to the equation x^2-12x=-10 ?
The solutions to the equation x^2-12x=-10 are x=6+sqrt(26),x=6-sqrt(26)
Find the zeros of x^2-12x=-10
The zeros of x^2-12x=-10 are x=6+sqrt(26),x=6-sqrt(26)