What are the solutions to the equation 3x^2-1x-4=0 ?

The solutions to the equation 3x^2-1x-4=0 are x= 4/3 ,x=-1

Find the zeros of 3x^2-1x-4=0

The zeros of 3x^2-1x-4=0 are x= 4/3 ,x=-1

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3 x^{2} - 1 x - 4 = 0

x = \frac{4}{3}, x = - 1

Decimal Notation

x = 1.33333 \dots, x = - 1

Solution steps

3 x^{2} - 1 \cdot x - 4 = 0

Refine

3 x^{2} - x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 4) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 3}

x = \frac{- ( - 1 ) + 7}{2 \cdot 3} : \frac{4}{3}

x = \frac{- ( - 1 ) - 7}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 1

3 x^{2} - 6 x + 24 = 0

(x - 6)^{2} - 8 x = 0

0 = \frac{2}{3} (x - 1) (x + 3)

x, x^{2} - 3 x - 10 = 0

x, x^{2} - 3 x - 4 = 0

What are the solutions to the equation 3x^2-1x-4=0 ?
The solutions to the equation 3x^2-1x-4=0 are x= 4/3 ,x=-1
Find the zeros of 3x^2-1x-4=0
The zeros of 3x^2-1x-4=0 are x= 4/3 ,x=-1