What are the solutions to the equation 1-1.3x+0.4x^2=0 ?

The solutions to the equation 1-1.3x+0.4x^2=0 are x=2,x= 5/4

Find the zeros of 1-1.3x+0.4x^2=0

The zeros of 1-1.3x+0.4x^2=0 are x=2,x= 5/4

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1 - 1.3 x + 0.4 x^{2} = 0

x = 2, x = \frac{5}{4}

Decimal Notation

x = 2, x = 1.25

Solution steps

1 - 1.3 x + 0.4 x^{2} = 0

Multiply both sides by

10

10 - 13 x + 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 13 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 4 \cdot 10}{2 \cdot 4}

(- 13)^{2} - 4 \cdot 4 \cdot 10 = 3

x_{1, 2} = \frac{- ( - 13 ) \pm 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 3}{2 \cdot 4}, x_{2} = \frac{- ( - 13 ) - 3}{2 \cdot 4}

x = \frac{- ( - 13 ) + 3}{2 \cdot 4} : 2

x = \frac{- ( - 13 ) - 3}{2 \cdot 4} : \frac{5}{4}

The solutions to the quadratic equation are:

x = 2, x = \frac{5}{4}

- y^{2} + 2 y

(y - 3)^{2} = 4

\frac{- 3 x ^{2} + 10800}{4} = 0

z, x^{2} + y^{2} + z^{2} = 4 z

x^{2} + 5 x - 14 = 0

What are the solutions to the equation 1-1.3x+0.4x^2=0 ?
The solutions to the equation 1-1.3x+0.4x^2=0 are x=2,x= 5/4
Find the zeros of 1-1.3x+0.4x^2=0
The zeros of 1-1.3x+0.4x^2=0 are x=2,x= 5/4