What are the solutions to the equation 6x^2-12x+8=0 ?

The solutions to the equation 6x^2-12x+8=0 are x=1+i(sqrt(3))/3 ,x=1-i(sqrt(3))/3

Find the zeros of 6x^2-12x+8=0

The zeros of 6x^2-12x+8=0 are x=1+i(sqrt(3))/3 ,x=1-i(sqrt(3))/3

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6 x^{2} - 12 x + 8 = 0

x = 1 + i \frac{3}{3}, x = 1 - i \frac{3}{3}

Solution steps

6 x^{2} - 12 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 \cdot 8}{2 \cdot 6}

Simplify

(- 12)^{2} - 4 \cdot 6 \cdot 8 : 43 i

x_{1, 2} = \frac{- ( - 12 ) \pm 4 3 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 3 i}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 4 3 i}{2 \cdot 6}

x = \frac{- ( - 12 ) + 4 3 i}{2 \cdot 6} : 1 + i \frac{3}{3}

x = \frac{- ( - 12 ) - 4 3 i}{2 \cdot 6} : 1 - i \frac{3}{3}

The solutions to the quadratic equation are:

x = 1 + i \frac{3}{3}, x = 1 - i \frac{3}{3}

x^{2} - 64 = 0

4 x^{2} + 12 x

6 x^{2} = - 19 x - 15

25 x^{2} + 4 = 20 x

1 0^{2} = 7^{2} + x^{2}

What are the solutions to the equation 6x^2-12x+8=0 ?
The solutions to the equation 6x^2-12x+8=0 are x=1+i(sqrt(3))/3 ,x=1-i(sqrt(3))/3
Find the zeros of 6x^2-12x+8=0
The zeros of 6x^2-12x+8=0 are x=1+i(sqrt(3))/3 ,x=1-i(sqrt(3))/3