What are the solutions to the equation 25x^2+4=20x ?

The solutions to the equation 25x^2+4=20x are x= 2/5

Find the zeros of 25x^2+4=20x

The zeros of 25x^2+4=20x are x= 2/5

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25 x^{2} + 4 = 20 x

x = \frac{2}{5}

Decimal Notation

x = 0.4

Solution steps

25 x^{2} + 4 = 20 x

Move

20 x

to the left side

25 x^{2} + 4 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

25 x^{2} - 20 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 25 \cdot 4}{2 \cdot 25}

(- 20)^{2} - 4 \cdot 25 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 20 )}{2 \cdot 25}

\frac{- ( - 20 )}{2 \cdot 25} = \frac{2}{5}

x = \frac{2}{5}

The solution to the quadratic equation is:

x = \frac{2}{5}

1 0^{2} = 7^{2} + x^{2}

x^{2} + 4 x - 5 = 0

2 x^{2} = - 28 x - 80

- 3 x^{2} - 6 x + 7

- 21 = 15 - 2 x^{2}

What are the solutions to the equation 25x^2+4=20x ?
The solutions to the equation 25x^2+4=20x are x= 2/5
Find the zeros of 25x^2+4=20x
The zeros of 25x^2+4=20x are x= 2/5