What are the solutions to the equation x^2-5x=x-5 ?

The solutions to the equation x^2-5x=x-5 are x=5,x=1

Find the zeros of x^2-5x=x-5

The zeros of x^2-5x=x-5 are x=5,x=1

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x^{2} - 5 x = x - 5

x = 5, x = 1

Solution steps

x^{2} - 5 x = x - 5

Move

5

to the left side

x^{2} - 5 x + 5 = x

Move

x

to the left side

x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

x = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

9^{2} + 4^{2} = c^{2}

x^{2} + 9 x^{2} - x - 9 = 0

x, \frac{( y _{2} )}{2} - \frac{( ( x + 2 ) ^{2} )}{4} = 1

x, 9 x^{2} + y^{2} - 9 z^{2} - 54 x - 4 y - 54 z + 4 = 0

3 x^{2} + 11 x - 7 = 0

What are the solutions to the equation x^2-5x=x-5 ?
The solutions to the equation x^2-5x=x-5 are x=5,x=1
Find the zeros of x^2-5x=x-5
The zeros of x^2-5x=x-5 are x=5,x=1