What are the solutions to the equation 8x^2-28x-60=0 ?

The solutions to the equation 8x^2-28x-60=0 are x=5,x=-3/2

Find the zeros of 8x^2-28x-60=0

The zeros of 8x^2-28x-60=0 are x=5,x=-3/2

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8 x^{2} - 28 x - 60 = 0

x = 5, x = - \frac{3}{2}

Decimal

x = 5, x = - 1.5

Solution steps

8 x^{2} - 28 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 8 ( - 60 )}{2 \cdot 8}

(- 28)^{2} - 4 \cdot 8 (- 60) = 52

x_{1, 2} = \frac{- ( - 28 ) \pm 52}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 52}{2 \cdot 8}, x_{2} = \frac{- ( - 28 ) - 52}{2 \cdot 8}

x = \frac{- ( - 28 ) + 52}{2 \cdot 8} : 5

x = \frac{- ( - 28 ) - 52}{2 \cdot 8} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 5, x = - \frac{3}{2}

r^{2} + \frac{4}{3} r = \frac{4}{3}

c, y^{2} + 2 x^{2} = c^{2}

2 = (1 - 2 (1) + 5) t^{2} + (2 (1) - 2 (1)) t + 1

- 12 x = 12 x^{2} + 3

x, 3 x^{2} + 3 y^{2} + 3 z^{2} + 2 x y - 2 yz + 2 x z = 0

What are the solutions to the equation 8x^2-28x-60=0 ?
The solutions to the equation 8x^2-28x-60=0 are x=5,x=-3/2
Find the zeros of 8x^2-28x-60=0
The zeros of 8x^2-28x-60=0 are x=5,x=-3/2