What are the solutions to the equation -12x=12x^2+3 ?

The solutions to the equation -12x=12x^2+3 are x=-1/2

Find the zeros of -12x=12x^2+3

The zeros of -12x=12x^2+3 are x=-1/2

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- 12 x = 12 x^{2} + 3

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

- 12 x = 12 x^{2} + 3

Switch sides

12 x^{2} + 3 = - 12 x

Move

12 x

to the left side

12 x^{2} + 3 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} + 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 12 \cdot 3}{2 \cdot 12}

1 2^{2} - 4 \cdot 12 \cdot 3 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 12}

x = \frac{- 12}{2 \cdot 12}

\frac{- 12}{2 \cdot 12} = - \frac{1}{2}

x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

x, 3 x^{2} + 3 y^{2} + 3 z^{2} + 2 x y - 2 yz + 2 x z = 0

\frac{s}{2} + \frac{s ^{2}}{2} - 3 = 0

5 a^{2} + 6 a - 147 = - 3

x^{2} = 4^{2} + 2^{2}

6 x^{2} + x - 3 = 0

What are the solutions to the equation -12x=12x^2+3 ?
The solutions to the equation -12x=12x^2+3 are x=-1/2
Find the zeros of -12x=12x^2+3
The zeros of -12x=12x^2+3 are x=-1/2