What are the solutions to the equation 6x^2+x-3=0 ?

The solutions to the equation 6x^2+x-3=0 are x=(-1+sqrt(73))/(12),x=(-1-sqrt(73))/(12)

Find the zeros of 6x^2+x-3=0

The zeros of 6x^2+x-3=0 are x=(-1+sqrt(73))/(12),x=(-1-sqrt(73))/(12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + x - 3 = 0

x = \frac{- 1 + 73}{12}, x = \frac{- 1 - 73}{12}

Decimal Notation

x = 0.62866 \dots, x = - 0.79533 \dots

Solution steps

6 x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 3) = 73

x_{1, 2} = \frac{- 1 \pm 73}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 73}{2 \cdot 6}, x_{2} = \frac{- 1 - 73}{2 \cdot 6}

x = \frac{- 1 + 73}{2 \cdot 6} : \frac{- 1 + 73}{12}

x = \frac{- 1 - 73}{2 \cdot 6} : \frac{- 1 - 73}{12}

The solutions to the quadratic equation are:

x = \frac{- 1 + 73}{12}, x = \frac{- 1 - 73}{12}

8 x^{2} - 5 x + 3 = 0

x^{2} - 3 x + 2 = 0

- 5 x^{2} + 12 x + 7 = 0

6 x^{2} + x - 8 = 0

(x + 8)^{2} = 16 - x^{2} + 9 x

What are the solutions to the equation 6x^2+x-3=0 ?
The solutions to the equation 6x^2+x-3=0 are x=(-1+sqrt(73))/(12),x=(-1-sqrt(73))/(12)
Find the zeros of 6x^2+x-3=0
The zeros of 6x^2+x-3=0 are x=(-1+sqrt(73))/(12),x=(-1-sqrt(73))/(12)