What are the solutions to the equation x^2+35=-12x ?

The solutions to the equation x^2+35=-12x are x=-5,x=-7

Find the zeros of x^2+35=-12x

The zeros of x^2+35=-12x are x=-5,x=-7

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x^{2} + 35 = - 12 x

x = - 5, x = - 7

Solution steps

x^{2} + 35 = - 12 x

Move

12 x

to the left side

x^{2} + 35 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 12 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 35 = 2

x_{1, 2} = \frac{- 12 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2}{2 \cdot 1}, x_{2} = \frac{- 12 - 2}{2 \cdot 1}

x = \frac{- 12 + 2}{2 \cdot 1} : - 5

x = \frac{- 12 - 2}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 5, x = - 7

t^{2} + 6 t + 5 = 0

z^{2} - 6 z

z^{2} + 8 z

z^{2} + 2 z

b^{2} = 25

What are the solutions to the equation x^2+35=-12x ?
The solutions to the equation x^2+35=-12x are x=-5,x=-7
Find the zeros of x^2+35=-12x
The zeros of x^2+35=-12x are x=-5,x=-7