What are the solutions to the equation 5x^2-40x-97=3 ?

The solutions to the equation 5x^2-40x-97=3 are x=10,x=-2

Find the zeros of 5x^2-40x-97=3

The zeros of 5x^2-40x-97=3 are x=10,x=-2

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5 x^{2} - 40 x - 97 = 3

x = 10, x = - 2

Solution steps

5 x^{2} - 40 x - 97 = 3

Move

3

to the left side

5 x^{2} - 40 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 5 ( - 100 )}{2 \cdot 5}

(- 40)^{2} - 4 \cdot 5 (- 100) = 60

x_{1, 2} = \frac{- ( - 40 ) \pm 60}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 60}{2 \cdot 5}, x_{2} = \frac{- ( - 40 ) - 60}{2 \cdot 5}

x = \frac{- ( - 40 ) + 60}{2 \cdot 5} : 10

x = \frac{- ( - 40 ) - 60}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

x = 10, x = - 2

- 3 x^{2} + 8 x - 5 = 0

4 z + z^{2} + 12 = 0

1 - x (- 5) - (- 5) + x^{2} = 0

(3 x + 4)^{2} = 24 x + 16

3 x^{2} + x = 1

What are the solutions to the equation 5x^2-40x-97=3 ?
The solutions to the equation 5x^2-40x-97=3 are x=10,x=-2
Find the zeros of 5x^2-40x-97=3
The zeros of 5x^2-40x-97=3 are x=10,x=-2