What are the solutions to the equation 0=3x^2-4x+2 ?

The solutions to the equation 0=3x^2-4x+2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3

Find the zeros of 0=3x^2-4x+2

The zeros of 0=3x^2-4x+2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3

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0 = 3 x^{2} - 4 x + 2

x = \frac{2}{3} + i \frac{2}{3}, x = \frac{2}{3} - i \frac{2}{3}

Solution steps

0 = 3 x^{2} - 4 x + 2

Switch sides

3 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 2 : 22 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2 i}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 2 i}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 2 i}{2 \cdot 3} : \frac{2}{3} + i \frac{2}{3}

x = \frac{- ( - 4 ) - 2 2 i}{2 \cdot 3} : \frac{2}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{2}{3}, x = \frac{2}{3} - i \frac{2}{3}

- 2 x^{(2)} + 3 x - 5 = 0

x, z = x^{2} + y^{2} - 5 x y - 23 x + 26 y + 9

v, K = \frac{1}{2} m v^{2}

3 x^{2} + 31 = 79

16 (\frac{x + 6}{4})^{2} + 8 (\frac{x + 6}{4}) + 1 = 0

What are the solutions to the equation 0=3x^2-4x+2 ?
The solutions to the equation 0=3x^2-4x+2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3
Find the zeros of 0=3x^2-4x+2
The zeros of 0=3x^2-4x+2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3