What are the solutions to the equation 4/3 x^2-4x+10/3 =0 ?

The solutions to the equation 4/3 x^2-4x+10/3 =0 are x= 3/2+i 1/2 ,x= 3/2-i 1/2

Find the zeros of 4/3 x^2-4x+10/3 =0

The zeros of 4/3 x^2-4x+10/3 =0 are x= 3/2+i 1/2 ,x= 3/2-i 1/2

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\frac{4}{3} x^{2} - 4 x + \frac{10}{3} = 0

x = \frac{3}{2} + i \frac{1}{2}, x = \frac{3}{2} - i \frac{1}{2}

Solution steps

\frac{4}{3} x^{2} - 4 x + \frac{10}{3} = 0

Multiply both sides by

3

4 x^{2} - 12 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 10}{2 \cdot 4}

Simplify

(- 12)^{2} - 4 \cdot 4 \cdot 10 : 4 i

x_{1, 2} = \frac{- ( - 12 ) \pm 4 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 i}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 4 i}{2 \cdot 4}

x = \frac{- ( - 12 ) + 4 i}{2 \cdot 4} : \frac{3}{2} + i \frac{1}{2}

x = \frac{- ( - 12 ) - 4 i}{2 \cdot 4} : \frac{3}{2} - i \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{1}{2}, x = \frac{3}{2} - i \frac{1}{2}

3 x^{2} - 9 x + 16 = 178

- 5 x^{2} + 10 x = 0

x^{2} - 22 x + 96 = 0

3 x^{2} + 18 x - 6 = 0

x^{2} + 8 x + 15 = 48

What are the solutions to the equation 4/3 x^2-4x+10/3 =0 ?
The solutions to the equation 4/3 x^2-4x+10/3 =0 are x= 3/2+i 1/2 ,x= 3/2-i 1/2
Find the zeros of 4/3 x^2-4x+10/3 =0
The zeros of 4/3 x^2-4x+10/3 =0 are x= 3/2+i 1/2 ,x= 3/2-i 1/2