What are the solutions to the equation -x^2-8x+3=0 ?

The solutions to the equation -x^2-8x+3=0 are x=-4-sqrt(19),x=sqrt(19)-4

Find the zeros of -x^2-8x+3=0

The zeros of -x^2-8x+3=0 are x=-4-sqrt(19),x=sqrt(19)-4

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- x^{2} - 8 x + 3 = 0

x = - 4 - 19, x = 19 - 4

Decimal Notation

x = - 8.35889 \dots, x = 0.35889 \dots

Solution steps

- x^{2} - 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

(- 8)^{2} - 4 (- 1) \cdot 3 = 219

x_{1, 2} = \frac{- ( - 8 ) \pm 2 19}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 19}{2 ( - 1 )}, x_{2} = \frac{- ( - 8 ) - 2 19}{2 ( - 1 )}

x = \frac{- ( - 8 ) + 2 19}{2 ( - 1 )} : - 4 - 19

x = \frac{- ( - 8 ) - 2 19}{2 ( - 1 )} : 19 - 4

The solutions to the quadratic equation are:

x = - 4 - 19, x = 19 - 4

\frac{1}{x + 1} > \frac{2}{x - 1}

ab + ah

30 \cdot \frac{π}{180}

(4 - 6 i)^{2}

10 \cdot 8

What are the solutions to the equation -x^2-8x+3=0 ?
The solutions to the equation -x^2-8x+3=0 are x=-4-sqrt(19),x=sqrt(19)-4
Find the zeros of -x^2-8x+3=0
The zeros of -x^2-8x+3=0 are x=-4-sqrt(19),x=sqrt(19)-4