What are the solutions to the equation (x-2)^2+(x+2)^2=2 ?

The solutions to the equation (x-2)^2+(x+2)^2=2 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of (x-2)^2+(x+2)^2=2

The zeros of (x-2)^2+(x+2)^2=2 are x=sqrt(3)i,x=-sqrt(3)i

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(x - 2)^{2} + (x + 2)^{2} = 2

x = 3 i, x = - 3 i

Solution steps

(x - 2)^{2} + (x + 2)^{2} = 2

Expand

(x - 2)^{2} + (x + 2)^{2} : 2 x^{2} + 8

2 x^{2} + 8 = 2

Move

2

to the left side

2 x^{2} + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

0^{2} - 4 \cdot 2 \cdot 6 : 43 i

x_{1, 2} = \frac{- 0 \pm 4 3 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 4 3 i}{2 \cdot 2}, x_{2} = \frac{- 0 - 4 3 i}{2 \cdot 2}

x = \frac{- 0 + 4 3 i}{2 \cdot 2} : 3 i

x = \frac{- 0 - 4 3 i}{2 \cdot 2} : - 3 i

The solutions to the quadratic equation are:

x = 3 i, x = - 3 i

2 x^{2} - 5 x - 12 = 0

x^{2} - 4 x - 91 = 7

0 = 3 x^{2} - 6 x + 1

x^{2} - 9 x = - 10

1^{2} + y^{2} = 4

What are the solutions to the equation (x-2)^2+(x+2)^2=2 ?
The solutions to the equation (x-2)^2+(x+2)^2=2 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of (x-2)^2+(x+2)^2=2
The zeros of (x-2)^2+(x+2)^2=2 are x=sqrt(3)i,x=-sqrt(3)i