What are the solutions to the equation -3x^2+2x+8=0 ?

The solutions to the equation -3x^2+2x+8=0 are x=-4/3 ,x=2

Find the zeros of -3x^2+2x+8=0

The zeros of -3x^2+2x+8=0 are x=-4/3 ,x=2

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- 3 x^{2} + 2 x + 8 = 0

x = - \frac{4}{3}, x = 2

Decimal Notation

x = - 1.33333 \dots, x = 2

Solution steps

- 3 x^{2} + 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) \cdot 8}{2 ( - 3 )}

2^{2} - 4 (- 3) \cdot 8 = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 ( - 3 )}, x_{2} = \frac{- 2 - 10}{2 ( - 3 )}

x = \frac{- 2 + 10}{2 ( - 3 )} : - \frac{4}{3}

x = \frac{- 2 - 10}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = 2

4 x^{2} - 14 x = 8

\frac{x ^{2}}{5} + \frac{x}{4} = 5

3 y^{2} - 12 = 0

3 x^{2} + 18 x - 1

x^{2} - 18 x + 20 = 3

What are the solutions to the equation -3x^2+2x+8=0 ?
The solutions to the equation -3x^2+2x+8=0 are x=-4/3 ,x=2
Find the zeros of -3x^2+2x+8=0
The zeros of -3x^2+2x+8=0 are x=-4/3 ,x=2