What are the solutions to the equation 3y^2-12=0 ?

The solutions to the equation 3y^2-12=0 are y=2,y=-2

Find the zeros of 3y^2-12=0

The zeros of 3y^2-12=0 are y=2,y=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 y^{2} - 12 = 0

y = 2, y = - 2

Solution steps

3 y^{2} - 12 = 0

Move

12

to the right side

3 y^{2} = 12

Divide both sides by

3

y^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 4, y = - 4

4 = 2

- 4 = - 2

y = 2, y = - 2

3 x^{2} + 18 x - 1

x^{2} - 18 x + 20 = 3

5 x^{2} - 4 x + 4 = 0

8 (4 x - 1) (x + 3) = 0

y^{2} - 4 y - 2 = 0

What are the solutions to the equation 3y^2-12=0 ?
The solutions to the equation 3y^2-12=0 are y=2,y=-2
Find the zeros of 3y^2-12=0
The zeros of 3y^2-12=0 are y=2,y=-2