What are the solutions to the equation quadraticformula x^2+7x+10=0 ?

The solutions to the equation quadraticformula x^2+7x+10=0 are x=-2,x=-5

Find the zeros of quadraticformula x^2+7x+10=0

The zeros of quadraticformula x^2+7x+10=0 are x=-2,x=-5

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x^{2} + 7 x + 10 = 0

x = - 2, x = - 5

Solution steps

x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 \cdot 1}, x_{2} = \frac{- 7 - 3}{2 \cdot 1}

x = \frac{- 7 + 3}{2 \cdot 1} : - 2

x = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

x^{2} - 20 x + 200 = 0

x^{2} + 8 x - 1 = 0

x^{2} + 17 x + 12 = 0

\frac{x ^{2}}{4} + \frac{3 x}{2} = 6

x^{2} - 3 x + 4

What are the solutions to the equation quadraticformula x^2+7x+10=0 ?
The solutions to the equation quadraticformula x^2+7x+10=0 are x=-2,x=-5
Find the zeros of quadraticformula x^2+7x+10=0
The zeros of quadraticformula x^2+7x+10=0 are x=-2,x=-5