What are the solutions to the equation x(3x+10)=77 ?

The solutions to the equation x(3x+10)=77 are x= 11/3 ,x=-7

Find the zeros of x(3x+10)=77

The zeros of x(3x+10)=77 are x= 11/3 ,x=-7

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x (3 x + 10) = 77

x = \frac{11}{3}, x = - 7

Decimal Notation

x = 3.66666 \dots, x = - 7

Solution steps

x (3 x + 10) = 77

Expand

x (3 x + 10) : 3 x^{2} + 10 x

3 x^{2} + 10 x = 77

Move

77

to the left side

3 x^{2} + 10 x - 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 77 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 77) = 32

x_{1, 2} = \frac{- 10 \pm 32}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 32}{2 \cdot 3}, x_{2} = \frac{- 10 - 32}{2 \cdot 3}

x = \frac{- 10 + 32}{2 \cdot 3} : \frac{11}{3}

x = \frac{- 10 - 32}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = \frac{11}{3}, x = - 7

1^{2} + x^{2} = 8^{2}

2 x^{2} + 36 = 6 x

(x - 4)^{2} = - 1

(x - 4)^{2} = 19

x^{2} - 9 x + 36 = 0

What are the solutions to the equation x(3x+10)=77 ?
The solutions to the equation x(3x+10)=77 are x= 11/3 ,x=-7
Find the zeros of x(3x+10)=77
The zeros of x(3x+10)=77 are x= 11/3 ,x=-7