What are the solutions to the equation 3x^2+20x+13=-4 ?

The solutions to the equation 3x^2+20x+13=-4 are x=-1,x=-17/3

Find the zeros of 3x^2+20x+13=-4

The zeros of 3x^2+20x+13=-4 are x=-1,x=-17/3

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3 x^{2} + 20 x + 13 = - 4

x = - 1, x = - \frac{17}{3}

Decimal Notation

x = - 1, x = - 5.66666 \dots

Solution steps

3 x^{2} + 20 x + 13 = - 4

Move

4

to the left side

3 x^{2} + 20 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 3 \cdot 17}{2 \cdot 3}

2 0^{2} - 4 \cdot 3 \cdot 17 = 14

x_{1, 2} = \frac{- 20 \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 20 + 14}{2 \cdot 3}, x_{2} = \frac{- 20 - 14}{2 \cdot 3}

x = \frac{- 20 + 14}{2 \cdot 3} : - 1

x = \frac{- 20 - 14}{2 \cdot 3} : - \frac{17}{3}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{17}{3}

- 2034 x^{2} + 170086 x - 6426 = 0

\frac{x ^{2}}{4} = 5

\frac{x ^{2}}{4} = 1

- 5 x^{2} + 70 x - 295 = 0

a (x) = x^{2} + 3 x - 10

What are the solutions to the equation 3x^2+20x+13=-4 ?
The solutions to the equation 3x^2+20x+13=-4 are x=-1,x=-17/3
Find the zeros of 3x^2+20x+13=-4
The zeros of 3x^2+20x+13=-4 are x=-1,x=-17/3