What are the solutions to the equation -5x^2+70x-295=0 ?

The solutions to the equation -5x^2+70x-295=0 are x=7-sqrt(10)i,x=7+sqrt(10)i

Find the zeros of -5x^2+70x-295=0

The zeros of -5x^2+70x-295=0 are x=7-sqrt(10)i,x=7+sqrt(10)i

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- 5 x^{2} + 70 x - 295 = 0

x = 7 - 10 i, x = 7 + 10 i

Solution steps

- 5 x^{2} + 70 x - 295 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 ( - 5 ) ( - 295 )}{2 ( - 5 )}

Simplify

7 0^{2} - 4 (- 5) (- 295) : 1010 i

x_{1, 2} = \frac{- 70 \pm 10 10 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 70 + 10 10 i}{2 ( - 5 )}, x_{2} = \frac{- 70 - 10 10 i}{2 ( - 5 )}

x = \frac{- 70 + 10 10 i}{2 ( - 5 )} : 7 - 10 i

x = \frac{- 70 - 10 10 i}{2 ( - 5 )} : 7 + 10 i

The solutions to the quadratic equation are:

x = 7 - 10 i, x = 7 + 10 i

a (x) = x^{2} + 3 x - 10

x, x^{2} - 3 x y = 10

m x^{2} + (2 m - 3) x + m - 3 = 0

p, x p^{2} + (x - y) p + 1 - y = 0

15 x^{2} - 19 x + 6 = 0

What are the solutions to the equation -5x^2+70x-295=0 ?
The solutions to the equation -5x^2+70x-295=0 are x=7-sqrt(10)i,x=7+sqrt(10)i
Find the zeros of -5x^2+70x-295=0
The zeros of -5x^2+70x-295=0 are x=7-sqrt(10)i,x=7+sqrt(10)i