What are the solutions to the equation 27x^2+18x+3=0 ?

The solutions to the equation 27x^2+18x+3=0 are x=-1/3

Find the zeros of 27x^2+18x+3=0

The zeros of 27x^2+18x+3=0 are x=-1/3

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27 x^{2} + 18 x + 3 = 0

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

27 x^{2} + 18 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 27 \cdot 3}{2 \cdot 27}

1 8^{2} - 4 \cdot 27 \cdot 3 = 0

x_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 27}

x = \frac{- 18}{2 \cdot 27}

\frac{- 18}{2 \cdot 27} = - \frac{1}{3}

x = - \frac{1}{3}

The solution to the quadratic equation is:

x = - \frac{1}{3}

0 = 3 x - x^{2}

x, x^{2} - 8 x + 15 = y

x^{2} + 5 x = 234

X^{2} + 10 X + 25 = 0

- 3 x^{2} + 6 x - 5

What are the solutions to the equation 27x^2+18x+3=0 ?
The solutions to the equation 27x^2+18x+3=0 are x=-1/3
Find the zeros of 27x^2+18x+3=0
The zeros of 27x^2+18x+3=0 are x=-1/3