What are the solutions to the equation completesquare 2x^2-9x+7=0 ?

The solutions to the equation completesquare 2x^2-9x+7=0 are x= 7/2 ,x=1

Find the zeros of completesquare 2x^2-9x+7=0

The zeros of completesquare 2x^2-9x+7=0 are x= 7/2 ,x=1

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2 x^{2} - 9 x + 7 = 0

x = \frac{7}{2}, x = 1

Decimal Notation

x = 3.5, x = 1

Solution steps

2 x^{2} - 9 x + 7 = 0

Move

7

to the right side

2 x^{2} - 9 x = - 7

Divide both sides by

2

\frac{2 x ^{2} - 9 x}{2} = \frac{- 7}{2}

x^{2} - \frac{9 x}{2} = - \frac{7}{2}

Rewrite in the form

(x + a)^{2} = b

(x - \frac{9}{4})^{2} = \frac{25}{16}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{9}{4} = \frac{25}{16} : x = \frac{7}{2}

Solve

x - \frac{9}{4} = - \frac{25}{16} : x = 1

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = 1

x, (x + y)^{2} = 16

x, 3 z = - y^{2} + x^{2}

- 3 x^{2} + 24 x + 144 = 0

- 3 x^{2} + 2 x - 4 = 0

x^{2} + 16 = 7 x

What are the solutions to the equation completesquare 2x^2-9x+7=0 ?
The solutions to the equation completesquare 2x^2-9x+7=0 are x= 7/2 ,x=1
Find the zeros of completesquare 2x^2-9x+7=0
The zeros of completesquare 2x^2-9x+7=0 are x= 7/2 ,x=1